the gas in the discharge cell of a laser contains(in mole percent) 11%co2, 5.3%N2 and 84%He.
what is the molar mass of this mixture?
(0.11*molar mass CO2) + (0.053*molar mass N2) + (0.84*molar mass He) = ??
To calculate the molar mass of the gas mixture, you need to know the molar masses of the individual gases and their respective mole percentages.
First, let's find the molar mass of each gas:
- Carbon dioxide (CO2): Molar mass (C) = 12.01 g/mol, Molar mass (O) = 16.00 g/mol
Molar mass (CO2) = Molar mass (C) + 2 * Molar mass (O) = 12.01 g/mol + 2 * 16.00 g/mol = 44.01 g/mol
- Nitrogen (N2): Molar mass (N) = 14.01 g/mol
Molar mass (N2) = 2 * Molar mass (N) = 2 * 14.01 g/mol = 28.02 g/mol
- Helium (He): Molar mass (He) = 4.00 g/mol
Now, let's calculate the weighted average molar mass of the gas mixture:
Molar mass of the mixture = (Molar mass of CO2 * Mole percentage of CO2) + (Molar mass of N2 * Mole percentage of N2) + (Molar mass of He * Mole percentage of He)
Molar mass of the mixture = (44.01 g/mol * 11%) + (28.02 g/mol * 5.3%) + (4.00 g/mol * 84%)
Let's plug in the values and calculate:
Molar mass of the mixture = (0.1101 * 44.01 g/mol) + (0.053 * 28.02 g/mol) + (0.84 * 4.00 g/mol)
Now, you can perform the calculations to get the numerical value.
Therefore, the molar mass of the gas mixture is the numerical result you obtained by evaluating the above equation.