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calculus

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2 forces F1 = 2i-3j and F2 = 3i + 12j are applied at a point. What force F must be applied at the point to counteract the resultant of these 2 forces?

  • calculus -

    R=F1+F2
    F=-R=-F1-F2=-2i+3j-3i-12j combine terms.

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