How many rpm's will a 2'' Nd45 sphere do spinning at 340.29 m/s.
Please help me!! =(
To determine the number of rotations per minute (RPM) of a spinning object, we need to calculate the angular velocity in rad/s and then convert it to RPM.
The angular velocity (ω) is given by the formula:
ω = v / r
Where:
- ω is the angular velocity in rad/s
- v is the linear velocity in m/s
- r is the radius of the sphere in meters
In this case, the linear velocity (v) is given as 340.29 m/s and the radius (r) is 2 inches, which is equivalent to 0.05 meters. So we can calculate the angular velocity as follows:
ω = 340.29 m/s / 0.05 m
ω ≈ 6805.8 rad/s
To convert the angular velocity to RPM, we use the conversion factor: 1 rad/s = 60 RPM. Therefore, we can calculate the RPM as follows:
RPM = ω * (60 / 2π)
RPM = 6805.8 * (60 / 2π)
RPM ≈ 64936
So, a 2'' Nd45 sphere spinning at 340.29 m/s will have approximately 64,936 RPM.