posted by Anonymous .
At 350 K, Kc = 0.142 for the reaction
2BrCl(g) *) Br2(g) + Cl2(g)
An equilibrium mixture at this temperature
contains equal concentrations of bromine and
chlorine, 0.067 mol/L. What is the equilib-
rium concentration of BrCl?
Answer in units of M.
Anonymous, check your 2-11-11,12:00am post.
what is the entire equation because you should be able to set it up as kc=(concentrations of products)/(concentrations of reactants). Also the balanced chemical equation will tell you to what power the concentration is raised to.
2BrCl ==> Br2 + Cl2
K = 0.142 = (Br2)(Cl2)/(BrCl)^2
Substitute and solve for the only unknown you have; i.e., (BrCl)