A rectangular sheet of
aluminum foil is 50 centimeters long and 20 centimeters
wide, and weighs 5.4 grams. Find the thickness
of the aluminum foil in centimeters.
D = kg/V = 2700kg/m^3.
5.4*10^-3 / V = 2700,
V = 5.4*10^-3 / 2.7*10^3 = 2*10^-6.
V = 0.05 * 0.02 * T = 2*10^-6,
1*10^-3*T = 2*10^-6,
T = 2*10^-6 / 1*10^-3 = 2*10^-3m = 2mm.
A rectangular sheet of aluminum foil is 50 centimeters long and 20 centimeters wide, and weighs 5.4 grams. Find the thickness of the aluminum foil in centimeters.
To find the thickness of the aluminum foil, we can use the formula:
Density = Mass / (Length * Width * Thickness)
Given that the length (L) is 50 centimeters, the width (W) is 20 centimeters, and the mass (M) is 5.4 grams, we need to solve for the thickness (T) in centimeters.
Density = M / (L * W * T)
Since the density of aluminum is known to be 2.7 grams per cubic centimeter, we can substitute this value into the formula:
2.7 g/cm^3 = 5.4 g / (50 cm * 20 cm * T)
To solve for T, we can now rearrange the equation:
T = 5.4 g / (50 cm * 20 cm * 2.7 g/cm^3)
T = 0.004 cm
Therefore, the thickness of the aluminum foil is 0.004 centimeters.