We're supposed to be using the "substitution method"?
So, what would the answer be for:
6x-y=-4; 2x+2y=15 (_,_)
Eq1: 6X -Y = -4.
Eq2: 2X + 2Y = 15.
Solve for Y IN Eq1:
6X - Y = -4,
-Y = -6X -4,
Y = 6X + 4,
Substitute 6x + 4 for Y IN Eq2:
2X + 2(6X + 4) = 15,
2X + 12X + 8 = 15,
14X= 15 - 8 = 7,
X = 1/2.
Substitute 1/2 for X IN Eq1:
6 * 1/2 - Y = -4,
3 - Y = -4,
-Y = -7,
Y = 7.
Solution: (1/2, 7).