Calculate the specific volume of an air-vapour mixture when the temp=30 degree Celsius, water vapour content Mw=0.015 kg/kg, total pressure Pt=90kpa

Please any one can help me>

To calculate the specific volume of an air-vapour mixture, we can use the ideal gas law and the Dalton's law of partial pressures. Here's the step-by-step process:

1. Convert the temperature from Celsius to Kelvin.
- To convert Celsius to Kelvin, add 273.15 to the temperature.
- So, in this case, the temperature in Kelvin would be 30 + 273.15 = 303.15 K.

2. Calculate the partial pressure of water vapour (Pw).
- Multiply the water vapour content (Mw) by the total pressure (Pt).
- Pw = Mw * Pt
- In this case, Pw = 0.015 kg/kg * 90 kPa = 1.35 kPa

3. Calculate the partial pressure of dry air (Pa).
- Subtract Pw from Pt to get Pa.
- Pa = Pt - Pw
- In this case, Pa = 90 kPa - 1.35 kPa = 88.65 kPa

4. Calculate the specific volume (v).
- Use the ideal gas law: v = R * T / P
- R is the specific gas constant for dry air and is approximately 287 J/(kg·K).
- T is the temperature in Kelvin.
- P is the dry air partial pressure in kilopascals.
- v = (R * T) / P
- In this case, v = (287 J/(kg·K) * 303.15 K) / 88.65 kPa

5. Convert the specific volume to the desired unit.
- The specific volume calculated above will be in cubic meters per kilogram (m³/kg).
- You can convert it to other units such as liters per kilogram (L/kg) if needed.

By following these steps, you should be able to calculate the specific volume of the air-vapour mixture.