The length of a rectangle is fixed at 27cm. What widths will make the perimeter greater than 100cm?
P = 2L + 2W
54 + 2W >100
Thank you so so much. This was the first tme I have had to solve a problem of this sort, I had no clue where to begin. You have saved the day once again. I apprecite all your help!
You're very welcome, Kimi!
To find the widths that will make the perimeter of a rectangle greater than 100cm, we need to understand the formula for the perimeter of a rectangle and solve the inequality.
The formula for the perimeter of a rectangle is given by:
Perimeter = 2 * (Length + Width)
In this case, the length of the rectangle is fixed at 27cm. Let's denote the width of the rectangle as "w". Then we can rewrite the formula as:
Perimeter = 2 * (27 + w)
We want to find the widths that will make the perimeter greater than 100cm, so we need to solve the inequality:
2 * (27 + w) > 100
To simplify this, we can start by distributing the 2:
54 + 2w > 100
Next, we can subtract 54 from both sides:
2w > 46
Finally, we divide both sides by 2 to solve for "w":
w > 23
Therefore, any width greater than 23cm will make the perimeter of the rectangle greater than 100cm.