The length of a rectangular piece of property is 1 foot more that twice the width if the perimeter is 302 feet, find the length and width

Let's start by assigning variables to the given information. Let's say the width of the rectangular property is "w" feet.

According to the problem, the length is 1 foot more than twice the width. Therefore, the length would be (2w + 1) feet.

The perimeter of a rectangle is given by the formula: Perimeter = 2(length + width).

Now, we can substitute the given information into the formula to find the perimeter of the rectangle:

2((2w + 1) + w) = 302

Simplifying the equation:

2(2w + 1 + w) = 302
2(3w + 1) = 302
6w + 2 = 302
6w = 300
w = 50

So, the width of the rectangular property is 50 feet.

Now, we can find the length by substituting the value of the width into the expression we found earlier:

Length = 2w + 1
Length = 2(50) + 1
Length = 100 + 1
Length = 101

Therefore, the width is 50 feet and the length is 101 feet.

To find the length and width of the rectangular piece of property, you can use the information given about the perimeter being 302 feet.

Let's denote the width of the property as "w" (in feet).
According to the given information, the length is 1 foot more than twice the width, which can be represented as "2w + 1" (in feet).

The perimeter of a rectangle can be calculated by adding the lengths of all its sides. In this case, the perimeter can be expressed as:
Perimeter = 2(length + width)

Based on the given information:
302 = 2[(2w + 1) + w]

Simplifying the equation, we can distribute the 2 on the right side:
302 = 2(2w + 1 + w)
302 = 2(3w + 1)
302 = 6w + 2
300 = 6w
w = 50

Now we have found the width of the rectangular piece of property, which is 50 feet.

To find the length, we substitute the value of w back into the expression for the length:
Length = 2w + 1
Length = 2(50) + 1
Length = 100 + 1
Length = 101

Therefore, the length of the rectangular piece of property is 101 feet and the width is 50 feet.

50 feet

w = width

2w + 1 = length
P = 2w + 2L

302 = 2w + 2(2w + 1)
Solve for w, the width.
length = 2w + 1