the length of a rectangle is 10 inches more than its width. what are the dimensions of the rectangle if its perimeter is 80 inches?
P = 2L + 2W
80 = 2(W + 10) + 2W
80 = 4W + 20
60 = 4W
15 = W
To find the dimensions of the rectangle, we need to set up an equation based on the given information.
Let's assume the width of the rectangle is represented by "W" inches.
According to the problem, the length of the rectangle is 10 inches more than its width. So, the length can be represented as (W + 10) inches.
The formula for the perimeter of a rectangle is: Perimeter = 2 * (Length + Width)
Substituting the values into the equation, we have:
80 = 2 * ((W + 10) + W)
Simplifying this equation:
80 = 2 * (2W + 10)
80 = 4W + 20
Subtract 20 from both sides:
60 = 4W
Divide both sides by 4:
W = 15
Now that we have the width, we can find the length:
Length = W + 10 = 15 + 10 = 25
Therefore, the dimensions of the rectangle are 15 inches (width) and 25 inches (length).