Calculate the Mass of C6H12O6 needed ot generate 2575 KJ of energy
To calculate the mass of C6H12O6 needed to generate a specific amount of energy, we need to use the concept of molar mass and the principle of stoichiometry.
Step 1: Determine the balanced chemical equation for the reaction of C6H12O6 to generate energy. The combustion of glucose (C6H12O6) can be represented as follows:
C6H12O6 + O2 → CO2 + H2O
Step 2: Calculate the molar mass of C6H12O6 by summing up the atomic masses of its constituent elements. Using the atomic masses from the periodic table, we can find that the molar mass of C6H12O6 is approximately equal to 180.16 grams/mol.
Step 3: Calculate the energy released by the combustion of 1 mole of C6H12O6. According to the balanced equation, 1 mole of C6H12O6 generates 6 moles of CO2 and 6 moles of H2O. The energy released by the combustion of 1 mole of glucose is approximately 2800 KJ. Therefore, the energy released per mole of C6H12O6 is 2800 KJ.
Step 4: Use a proportion to calculate the mass of C6H12O6 needed to generate 2575 KJ of energy. We can set up the following proportion:
(2575 KJ) / (2800 KJ) = (x grams) / (1 mole)
Cross-multiplying and solving for x, we get:
x = (2575 KJ * 1 mole) / (2800 KJ)
x ≈ 0.919 moles
Step 5: Finally, calculate the mass of C6H12O6 using the molar mass and the number of moles calculated in the previous step:
Mass = (0.919 moles) * (180.16 grams/mole)
Mass ≈ 165.57 grams
Therefore, approximately 165.57 grams of C6H12O6 are needed to generate 2575 KJ of energy.