posted by John .
2 CO (g) + O2 (g) --> 2 CO2 (g)
The mechanism below has been proposed for this reaction;
(slow) O2 + CO --> CO2 + O
(fast) O + CO --> CO2
Based on this mechanism what is the rate law for this reaction?
Rate Law is determined by the slow step and any step that occurs before it. Just the sum of the slow step plus everything before it has to have the same reactants as the equation you're trying to get to. The exponents are determined by the coefficeints with them. Hope I helped. God Bless!!