__ NH4NO3 (s) --> __ NH2 (g) + __ HNO3 (l)

Please balance equation!

To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

Let's count the atoms of each element in the unbalanced equation:
On the left-hand side:
N: 1
H: 4
O: 3

On the right-hand side:
N: 2
H: 5
O: 4

Now, let's balance each element one by one:
Nitrogen (N): Since there are two nitrogen atoms on the right side, we need to balance the left side by placing a coefficient of 2 in front of NH4NO3.

2 NH4NO3 (s) --> __ NH2 (g) + __ HNO3 (l)

Hydrogen (H): There are 8 hydrogen atoms on the left side (4 from NH4 and 4 from NO3), while there are only 2 hydrogen atoms on the right side. To balance hydrogen, we can put a coefficient of 4 in front of NH2.

2 NH4NO3 (s) --> 4 NH2 (g) + __ HNO3 (l)

Oxygen (O): We have 12 oxygen atoms on the left side (3 from NH4NO3) and only 4 on the right side (from HNO3). To balance oxygen, we can place a coefficient of 6 in front of HNO3.

2 NH4NO3 (s) --> 4 NH2 (g) + 6 HNO3 (l)

Now the equation is balanced.