a ball is dropped 128 feet from the roof of a building with each bounce the ball goes up exactly half its previous height. A man is sitting at his desk on the second floor. How many times will he see the ball if his eye level is 15 feet above the ground?

Halves give you these bounces. You figure it out.

128, 64, 32, 16, 8, 4, 2, 1

is the answer 4X

is the answer 4 times

can u check my answer please

4 times

To determine how many times the man will see the ball, we need to find out how many times the ball will bounce back up to a height where it is visible to the man.

First, let's determine the maximum height the ball will bounce to after each bounce.

The ball is dropped from a height of 128 feet. After the first bounce, it will reach a height of half of its previous height, which is 128/2 = 64 feet. After the second bounce, it will reach a height of 64/2 = 32 feet. Similarly, the third bounce will take it to a height of 32/2 = 16 feet, and so on.

Now, let's see how many times the ball will bounce back up to a height where it is visible to the man. The man's eye level is at a height of 15 feet above the ground.

The ball needs to bounce back up to a height of at least 15 feet for the man to see it. Let's count the number of bounces:

1st bounce: 64 feet
2nd bounce: 32 feet
3rd bounce: 16 feet

After the third bounce, the ball will reach a height of 16 feet, which is higher than the man's eye level. Therefore, the man will see the ball three times.

So, the man will see the ball three times.