f(x)=x^3+2x^2-57x+54;k=6
What are the directions? It's not clear what to do.
Factor the polynomial given f(k) = 0.
To find the value of f(x) when k = 6, we need to substitute x = k = 6 into the given function f(x) = x^3 + 2x^2 - 57x + 54.
Step 1: Replace x with k in the function.
f(k) = k^3 + 2k^2 - 57k + 54
Step 2: Substitute k = 6 into the function.
f(6) = 6^3 + 2(6)^2 - 57(6) + 54
Step 3: Simplify the expression.
f(6) = 216 + 2(36) - 342 + 54
= 216 + 72 - 342 + 54
= -288
Therefore, when k = 6, f(x) is equal to -288.