calculus
posted by crystal .
the edge of a cube is increasing at the rate of .05 centimeters per second. in terms of the side of the cube s, what is the rate of change of the volume of the cube, in cm^3/sec

V = s^3
dV/dt = 3s^2 ds/dt
= 3s^2(.05)
= .15 s^2
I don't think your question was complete.
It probably said "what is the rate of change of the volume of the cube, in cm^3/sec, when s = ...."
Sub in the value of the given s into the dV/dt,
otherwise the above answer stands as is.
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