Repost- Calculus; someone please help

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Please help out. Thank you.
A right triangle has one leg on the x-axis. The vertex at the right end of that leg is at the point (3,0). The other vertex touches the graph os y=e^x. the entire triangle is to lie in the first quadrant. Find the maximum area of this triangle.Justify your answer.

My work:
A= (3-x)y/2
y=e^x
A=(3-x)(e^x)/2 <-- is this the right equation?

Thanks.


No one has answered this question yet.

  • Repost- Calculus; someone please help -

    Yes it is the right equation. Good job!

  • Repost- Calculus; someone please help -

    is the max. area 3.6945?
    thanks.

  • Repost- Calculus; someone please help -

    Yes, that's correct too.

    In exams and in general, if the number is a "round" number like e⊃2/2, I would give the answer as e²/2=3.6945(approx.)
    because the latter is an approximation. This will give the exact value as the answer.

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