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algebra

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How do you multipl (3a-2b)(4a+3b)??

  • algebra -

    (3a-2b)(4a+3b)

    Using FOIL-first, outer, inner, last
    (3a - 2b)(4a + 3b)
    First = 3a * 4a = 12a^2
    Outer = 3a * 3b = 9ab
    Inner = -2b * 4a = -8ab
    Last = -2b * 3b = -6b^2

    12a^2 + 9ab - 8ab - 6b^2
    Combine like terms
    12a^2 + ab - 6b^2

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