if a dog runs 6 meters in 1 second and then at the end of the second second the dog ran an additional 4 meters. what would describe the dogs motion in both seconds
A dog ran 10 meters in 2 seconds. What was the dog's speed? (Use the equation s = d ÷ t.)
To describe the dog's motion in both seconds, we need to determine the distance it covered in each second.
In the first second, the dog ran 6 meters.
In the second second, the dog ran an additional 4 meters.
Therefore, the total distance covered by the dog in the first two seconds is 6 + 4 = 10 meters.
So, the dog's motion can be described as covering a distance of 6 meters in the first second and an additional 4 meters in the second second, resulting in a total distance of 10 meters in the first two seconds.