Consider the freight train. Suppose 15 boxcars pass by in a time of 14.0 s and each has a length of 14.0 m.
(a) What is the frequency at which each boxcar passes?
(b) What is the speed of the train?
(a) Well, the frequency at which each boxcar passes would just be the reciprocal of the time it takes for all 15 boxcars to pass by. So, the frequency would be "one over 14.0 s divided by 15." But let's not get too mathematical here, because let's face it, trains and math don't mix well. So, the frequency at which each boxcar passes is like trying to catch a mechanical bull riding a unicycle while juggling flaming torches. It's tricky!
(b) Now, the speed of the train is a whole different beast. To find that, we need to know the total distance traveled by the train, which is the combined length of all the boxcars. So, that would be 14.0 m times 15 boxcars. After multiplying, we get a number that's longer than a clown's never-ending tie!
Now, to calculate the speed, we take the total distance traveled and divide it by the total time it took for all the boxcars to pass by. In other words, it's like watching a snail race against a cheetah. The snail goes at its own pace, slowly inching forward, while the cheetah zooms past like lightning. It's all about finding the balance between speed and slowness.
So, to sum it up, the frequency is as tricky as a one-legged clown trying to tap dance. And the speed is like watching a snail and a cheetah compete in a race. Stay tuned for the thrilling conclusion!
(a) To find the frequency at which each boxcar passes, we need to divide the total number of boxcars by the total time taken.
Given:
Number of boxcars = 15
Total time taken = 14.0 s
Frequency = Number of boxcars / Total time taken
Frequency = 15 / 14.0
Frequency = 1.071 Hz
Therefore, the frequency at which each boxcar passes is approximately 1.071 Hz.
(b) The speed of the train can be calculated by considering the distance traveled and the time taken.
Given:
Length of each boxcar = 14.0 m
Number of boxcars = 15
Total time taken = 14.0 s
Distance traveled = Length of each boxcar * Number of boxcars
Distance traveled = 14.0 m * 15
Distance traveled = 210.0 m
Speed = Distance traveled / Total time taken
Speed = 210.0 m / 14.0 s
Speed ≈ 15.0 m/s
Therefore, the speed of the train is approximately 15.0 m/s.
To find the frequency at which each boxcar passes, we need to divide the total number of boxcars passing by the total time it takes.
(a) To calculate the frequency:
Frequency = Total number of boxcars / Total time
Frequency = 15 boxcars / 14.0 s
Therefore, the frequency at which each boxcar passes is 15/14.0 Hz or approximately 1.07 Hz.
(b) To find the speed of the train, we need to know the distance traveled by the train in a given time. As each boxcar has a length of 14.0 m, the distance traveled by the train can be calculated by multiplying the length of one boxcar by the total number of boxcars.
Distance traveled by the train = Length of one boxcar × Total number of boxcars
Distance traveled by the train = 14.0 m × 15 boxcars
Therefore, the distance traveled by the train is 210 m.
Now, we can calculate the speed of the train using the formula:
Speed = Distance / Time
In this case, the distance traveled by the train is 210 m, and the time taken is 14.0 s.
Speed = 210 m / 14.0 s
Therefore, the speed of the train is 15 m/s.
(a) 15 boxcars/14 s = 1.071 per second
(b) (15 boxcars*14 meters/boxcar)/14 s
= 15 meters/s