Algebra II
posted by Attalah .
Solve each equation. Check for extraneous solutions.
Solve:x+5=3x7
My answers were: x=6 and x=.5
I don't think they are right though, but I should get 2 answers right???....Help!

6 is correct.
If you check your answers, you will find that .5 (1/2) is not a solution.
You must always check your answers in the original problem. 
So i wouldn't have 2 answers?

One answer, x = 6.
.5 or 1/2 is an extraneous solution (not a valid solution).
If you are asked specifically if there are any extraneous solutions, then you would list it as such.
I've never had a problem ask for extraneous solutions, since it's not a solution to the problem. 
ok so would 2y3=3y2 be y=1??

No, y = 1 is an extraneous solution.
y = 1, is the answer. 
4w+32=5
Would be: w= 5\4 
How would I solve:
2z+13=z2
???