Discrete Math
posted by Laurey .
Consider the following relations on R, the set of real numbers
a. R1: x, y ∈ R if and only if x = y.
b. R2: x, y ∈ R if and only if x ≥ y.
c. R3 : x, y ∈ R if and only if xy < 0.
Determine whether or not each relation is flexible, symmetric, antisymmetric, or transitive. For each property not possessed by the relation, provide a convincing example. Summarize the results in the table below. What of these are equivalence relations?

Recall the definitions of the four properties:
a ~ a. (Reflexivity)
if a ~ b then b ~ a. (Symmetry)
if a~b ∧ b~a > a=b (antisymmetry)
if a ~ b and b ~ c then a ~ c. (Transitivity)
Example:
R2: x, y ∈R iff x≥y
reflexive: x≥x
not symmetric: x≥y > y≥x (false)
antisymmetric: x≥y ∧ y≥x > x=y
transitive: x≥y ∧ y≥z > x≥z
I will leave R1 and R3 for you as an exercise
Post if you need more detailed explanations. 
Thank you MathMate for your quick reply! I think I understand it a lot better after your post, but I still feel a little fuzzy. So for R1:
Reflexive: x = x
Symmetric: x = y, then y = x
antisymmetric: x = y and y = x that implies x = y (?)
Transitive: x = y and y = z, then x = z
Am I semion the right track? Also, for R3 a little confused. Thanks so much for your help. I really appreciate it! 
All correct. It is possible that a relation is both symmetric AND antisymmetric. No worries.
Continue with R3 and post if you are not sure. Keep up the good work. 
R3:
Not Reflexive: x ⊀ x
Symmetric:
Antisymmetric:
Not Transitive:
I'm not sure how to justify. . . the xy and 0 is throwing me off. . .can you separate them? If that makes any sense. . .I'm lost.
But R2 would be considered an equivalent relation because it is reflexive, transitive, and symmetric. Thanks again for all your help. 
Correct about the requirements for equivalent relations: reflexive, symmetric and transitive.
However, R2 is not symmetric, so it is not an equivalent relation. Check R1 instead.
For R3, this is how you would proceed:
R2: x, y ∈R iff xy<0
not reflexive: x*x<0 (false, x*x ≥0 ∀x)
symmetric: if xy<0 > yx<0
not antisymmetric: if xy<0 & yx<0 > x=y (false)
not transitive: xy<0 and yz<0 > xz<0 (false: for example, 1*2<0 and 2*(3)<0 > (1)*(3)<0 is false) 
Oh yea I meant to type R1, sorry it was a typo. Thank you for your help MathMate!

You're welcome!