Calculate the amount of Citric acid monohydrate needed to make 100 mL of 0.1 M solution
M = moles/L
Solve for moles.
moles = grams/molar mass
Solve for grams.
To calculate the amount of Citric acid monohydrate needed to make a 0.1 M solution, you will need to know the molar mass of Citric acid monohydrate and the desired volume of the solution.
1. Find the molar mass of Citric acid monohydrate (H3C6H5O7.H2O):
- Atomic mass of hydrogen (H) = 1 g/mol
- Atomic mass of carbon (C) = 12 g/mol
- Atomic mass of oxygen (O) = 16 g/mol
- Molecular mass of Citric acid (C6H8O7) = (6 * 12) + (8 * 1) + (7 * 16) = 192 g/mol
- Molecular mass of water (H2O) = (2 * 1) + (1 * 16) = 18 g/mol
- Molar mass of Citric acid monohydrate = 192 + 18 = 210 g/mol
2. Use the formula for molarity to calculate the amount of Citric acid monohydrate:
Molarity (M) = moles of solute / volume of solution (L)
Given that the desired volume of the solution is 100 mL (which is equal to 0.1 L), we can rearrange the formula to solve for moles of solute:
Moles of solute = Molarity * Volume of solution (L)
Moles of Citric acid monohydrate = 0.1 mol/L * 0.1 L = 0.01 moles
3. Finally, find the mass of Citric acid monohydrate needed using the calculated moles and molar mass:
Mass = Moles of solute * Molar mass
Mass = 0.01 moles * 210 g/mol = 2.1 grams
Therefore, you would need 2.1 grams of Citric acid monohydrate to make a 0.1 M solution in 100 mL of solvent.
To calculate the amount of Citric acid monohydrate needed to make a 0.1 M solution, we need to know the molar mass of Citric acid monohydrate and the volume of the solution we want to make.
The molar mass of Citric acid monohydrate is:
Citric acid (C₆H₈O₇) has a molar mass of 192.13 g/mol.
Monohydrate means it has one water molecule (H₂O) attached to it. The molar mass of water is 18.02 g/mol.
So, the molar mass of Citric acid monohydrate is 192.13 g/mol + 18.02 g/mol = 210.15 g/mol.
Now, we can use the formula:
Amount (in moles) = Concentration (in M) × Volume (in liters)
We want to make a 0.1 M solution of 100 mL. To use the formula, we need to convert the volume from milliliters to liters:
Volume (in liters) = 100 mL / 1000 mL/L = 0.1 L
Now we can calculate the amount in moles:
Amount (in moles) = 0.1 M × 0.1 L = 0.01 moles
Finally, we can calculate the mass of Citric acid monohydrate needed using the molar mass:
Mass (in grams) = Amount (in moles) × Molar mass (in g/mol)
= 0.01 moles × 210.15 g/mol
= 2.1015 grams
So, you will need approximately 2.1015 grams of Citric acid monohydrate to make a 0.1 M solution of 100 mL.