calculus
posted by nic .
PLEASE HELP Find the first and second derivatives of the function.
y = e^8ex. I keep getting y' = e^8ex * 8 and its wrong. how do you do this?

y=e^(8e^x)
use the chain rule,
dy/dx
= dy/d(8e^x) . d(8e^x)/dx
= e^(8e^x) . 8e^x
=8 e^(8e^x).e^x
=8 e^(8e^x+x)
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