Calculus

posted by .

1.If a body moves in a straight line according to the law s= 24t +3t^2 - t³, where s is the distance measured in meters from the origin and t is the time in seconds after it starts to move, calculate the body’s velocity as a function of time.

a.v = 30t – 3t²
b.v= 30t - t²
c.v = 24 + 3t- t^2
d.v = 24 +6t -3t²

I think it's D but also confused by A


2.what is the velocity of the body in question 10 when t = 3seconds?

a.15 m/s
b.27 m/s
c.63 m/s
d.81 n/s

I think it's A but confused it might by C.

can you help me .

  • Calculus -

    1) D
    2) v = 24 +6t -3t²
    when t = 3
    v = 24 +18 - 27
    v = 15 or in other words a.

  • Calculus -

    thank you!

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Math-acceleration

    An object moves across a straight line so that after t seconds, is distance from its starting point is: D(t)=t^3 - 12t^2 + 100t + 12 meters. Find the acceleration of the object after 3 seconds. I believe acceleration is calculated …
  2. kinematics

    these are two similar kinematics maths question which i don't know. Please help! 1)A particle moves in a straight line so that its distance, s metres, from a fixed point O is given by s = 2t^3 - 3t^2 - 12t + 6, where t is the time …
  3. Math

    Romeo and Juliet are moving in the xy-plane. Juliet starts at the point (0,20( and moves in a straight line at a constant speed. She will pass through the origin in exactly 5 seconds. Romeo starts at the same time from the point (30,0) …
  4. calculus

    A particle moves along a straight line with equation of motion s = f(t), where s is measured in meters and t in seconds. Find the velocity and speed when t = 9. f(t) = t ^-1 - t
  5. calculus

    A particle that moves along a straight line has velocity v(t)=(t^2)e^(-2t) meters per second after t seconds.?
  6. math

    A particle moves on a straight line. The velocity after t seconds is given by V= 3t^2 – 6t – 8. The distance of the particle from the origin after one second is 1o meters. Calculate the distance of the particle from the origin …
  7. calculus A

    A particle moves according to a law of motion s = f(t) = t3 - 12t2 + 21t, t 0, where t is measured in seconds and s in feet. v(t) = 3t^2 - 24t 21 a(t) = 6t - 24 e) Find the total distance traveled during the first 8 s. i) When is the …
  8. calculus

    a particle starts from rest and moves along a straight line with an acceleration equal to 24-15√t where distance and time are measured in terms of feet and seconds respectively. with what acceleration will the particle return …
  9. calculus

    a particle starts from rest and moves along a straight line with an acceleration equal to 24-15√t where distance and time are measured in terms of feet and seconds respectively. with what acceleration will the particle return …
  10. calculus

    a particle starts from rest and moves along a straight line with an acceleration equal to 24-15√t where distance and time are measured in terms of feet and seconds respectively. with what acceleration will the particle return …

More Similar Questions