Charged particles #1 and #2 are 0.4 cm apart in air and exert a 100 Nt on force each other. If the 2 charges (at the same distance) exert a 25 Nt for on each other in substance "blox", then "blox" has a dielectric constant of:
0, 4, 2, 2500, more info needed
E=q/episilion
episilion=4, E reduced to 1/4. Think about it, what does a dielectric do?
it's an electrical insulator...so I would set my equation up as
1/4 = q/4 ? Is this correct? But then my answer equals 1, which isn't an answer choice. I'm sorry, but I'm just not getting this...
What equation?
In a parallel field, E=q/episilion.
If E goes down by 4, episiolon has to increase by 4. The answer is 4.
To find the dielectric constant of the substance "blox", we can use the equation for electrical force between two charges in a medium:
F = (k * q1 * q2) / r^2
Where:
- F is the force between the charges
- k is the Coulomb's constant (9 x 10^9 N m^2/C^2)
- q1 and q2 are the magnitudes of the charges
- r is the distance between the charges
By comparing the forces in air and in "blox", we can use the following relationship:
F_blox = F_air / k_blox
Where:
- F_blox is the force between the charges in "blox"
- F_air is the force between the charges in air
- k_blox is the dielectric constant of "blox"
Given:
- F_air = 100 Nt
- F_blox = 25 Nt
- Distance (r) remains the same for both cases
Plugging in the values:
25 Nt = 100 Nt / k_blox
Simplifying the equation:
k_blox = 100 Nt / 25 Nt
k_blox = 4
Therefore, the dielectric constant of the substance "blox" is 4.