You have $110 IN YOUR lunch account and plan to spend $2.75 each school day.

a) Write and graph a linear equation that represents the balance in your lunch account

(i just need help making an equation for this problem)

b) How many school days will it take to spend all of the money in your lunch account?

much appreciation if you help me(: thanks u

x = number of days

y = 110 - 2.75x

(A) y=110-2.75x

Then graph that.
(B) 40 school days

(B) 40 school days

Dear Stephanie!

The answer to proublem A) is $110-2.75x x=The amount of days you spend $2.75

B) since x= 40 you graph 40

a) To write a linear equation that represents the balance in your lunch account, we can start by assuming the initial balance is $110. As you plan to spend $2.75 each school day, the balance after n school days would be remaining amount (which is the initial balance subtracted by the total spending).

Let's denote the balance after n days as B(n). We can express this balance as:

B(n) = Initial balance - Total spending

Since the total spending per day is $2.75 and n represents the number of school days, the total spending after n days would be: Total spending = $2.75 * n.

Plugging these values into the equation, we get:

B(n) = $110 - $2.75 * n

This is the linear equation that represents the balance in your lunch account.

For graphing, you can plot the number of school days (n) on the x-axis and the balance (B(n)) on the y-axis. Draw the graph using the equation B(n) = $110 - $2.75 * n. Each point on the graph will represent the balance after a certain number of school days.

b) To determine the number of school days it will take to spend all the money in your lunch account, we need to find the value of n when the balance (B(n)) becomes zero.

So, we can set the equation B(n) = $110 - $2.75 * n equal to zero and solve for n:

$110 - $2.75 * n = 0

$2.75 * n = $110 (by isolating the n-term)

n = $110 / $2.75

n ≈ 40

Therefore, it will take approximately 40 school days to spend all the money in your lunch account.

let x be ttl $ spent (2.75 * days)

y=110-x