pre calculus
posted by anonymous .
solve the equation. give an exact solution, and also an approximate solution to four decimal places.
2^(9x7)=7
My first step was to change it to
log(base 2) 7 = 9x7
i got 1.0897
Did i do something wrong or did i miss one question?

pre calculus 
Reiny
just take log of both sides
log (2^(9x7)) = log 7
(9x7) log2 = log7
9x  7 = log7/log2
etc.
your answer is correct, see
http://www.google.ca/search?hl=en&source=hp&q=%28%28log%287%29%2Flog%282%29%2B7%29%2F9&btnG=Google+Search&aq=f&aqi=&aql=&oq= 
pre calculus 
drwls
[9x 7] log 2 = log 7
Any log base can be used, as long as it is the same for both sides.
9x  7 = 2.807
9x = 9.807
x = 1.0897
Your answer is correct!
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