(2x(tothe2ndpower)-3x+4)-(3x(tothe2ndpower)-x+2= ????

2x^2 - 3x + 4 - (3x^2 - x + 2) = 0

-x^2 - 2x + 2 = 0
x^2 + 2x - 2 = 0

I will complete the square, in this case it is easier than using the formul
x^2 + 2x + 1 = 2+1
(x+1)^2 = 3
x+1 = ± ?3
x = -1 ± ?3