calculus
posted by Tyler .
Consider the function below.
f(x) = 4x2  5x
(a) Find f '(2).
(b) Use the answer in part (a) to find an equation of the tangent line to the parabola y = 4x2  5x at the point (2, 6).
y =

y = 4 x^2  5 x
y' = 8 x  5
at x = 2
y'(2) = 165 = 11
m = 2
y = m x + b
6 = 2 (2) + b
b = 2
so
y = 2 x + 2