calculus
posted by katrina .
suppose the endpoints of one side of a rotated square are (5,5) and (1,1). Find the dimensions and area of the square

d^2 = (1+5)^2 + (1+5)^2
d^2 = 36 + 16
d^2 = 52 = area
d = side length = sqrt(52) = 2 sqrt(13)
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