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suppose the endpoints of one side of a rotated square are (-5,-5) and (1,-1). Find the dimensions and area of the square

  • calculus -

    d^2 = (1+5)^2 + (-1+5)^2
    d^2 = 36 + 16
    d^2 = 52 = area
    d = side length = sqrt(52) = 2 sqrt(13)

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