Precalc

posted by .

chande into a single logarithm

(1/2)ln(x^(2)+1)-4ln(1/2)-((1/2)[ln(x-4)+lnx] )

steps to please

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Math (Calculus)

    Can somebody solve this logarithm problem step by step for me please: 2(lnx)² + lnx-1 = 0 First let y = ln x be a new variable, , and solve the polynomial 2 y^2 + y - 1 = 0 2(y +1)(y - 1/2) = 0 Solutions are y = -1 or +1/2 Thus x …
  2. Precalc

    how to write each expression into a single logarithm. 3log[4]x^(2) + (1/2)log[4]ã(x) the answer is: (25/4)log[4]x steps please
  3. Precalc

    how to write each expression into a single logarithm. ln(x-1/x) + ln(x/x+1) - ln((x^(2)-1)) the answer is: -2ln(x+1) steps please i tried solving this but ended up getting this long expression
  4. Math - Write expression as single logarithm

    Write the expression below as a single logarithm. Please show all of your work. ln((x^2 – 1)/(x^2 – 6x + 8)) – ln((x+1)/(x+2))
  5. Precalculus

    Write 4log2+log6-log3 as a single logarithm. Explain with steps please!~~
  6. MATH HELP!

    i have write the equation as a single logarithm 2 lnx-3 lny+1/2 lnz
  7. Calculus

    Write as a single logarithm of a single quantity ln(3)+1/2ln(x+2)-4ln(1+sqrtx)
  8. math

    1/7[4ln(x+9)-lnx-(x^2-25)]
  9. Math - Logarithms

    Write the following expression as a single logarithm: 4ln2x + ln(6/x) - 2ln2x So I did... 4ln2x + ln(6/x) - 2ln2x = ln2x^4 + ln(6/x) - ln2x^2 = ln16x^4 + ln(6/x) - ln4x^2 = ln16x^(2)(2) + ln(6/x) - ln4x^2 = 2ln16x^2 + ln6 - lnx - ln4x^2 …
  10. College Algebra

    I am asked to write a logarithmic expresion as a single logarithm with coefficient 1 and simplify as much as possible. The equation is: 4logbase5Y-3logbase5X+1/2logbase5Z. Could some please help me I am not understanding this whole …

More Similar Questions