In a gift wrapping department, a customer can choose from x different paper, y different ribbons and z different greeting cards. There are 160 different paper, ribbon, and greeting card combinations possible. List three of the possible combinations.

To find three of the possible combinations of paper, ribbon, and greeting cards, we can use the given information that there are x different paper options, y different ribbon options, and z different greeting card options.

We are also told that there are 160 different combinations in total. Therefore, to list three possible combinations, we can assume that x * y * z = 160.

Let's first find the factors of 160:

1 * 160 = 160
2 * 80 = 160
4 * 40 = 160
5 * 32 = 160
8 * 20 = 160
10 * 16 = 160

We need to find three combinations, so let's choose the first three factors:

Combination 1: x = 1, y = 160, z = 1
This means there is only one paper option, 160 ribbon options, and one greeting card option.

Combination 2: x = 2, y = 80, z = 1
This means there are two paper options, 80 ribbon options, and one greeting card option.

Combination 3: x = 4, y = 40, z = 1
This means there are four paper options, 40 ribbon options, and one greeting card option.

Please note that there can be many more combinations, but these are just three examples based on the given condition.