ALgebra...plz help
posted by Anonymous
If the tens digit of a twodigit number is subtracted from the units digit, the difference is 8. The number with the digits reversed is 10 more than nine times the units digit of the original number. Find the number.

tchrwill
Let the two digit number be 10A + B.
Then, from "If the tens digit of a twodigit number is subtracted from the units digit, the difference is 8.", or
B  A = 8.
From "The number with the digits reversed is 10 more than nine times the units digit of the original number.", 10B + A = 9B + 10.
Substituting A = B  8 into 10B + A = 9B + 10 yields 10B + B  8 = 9B + 10 or 11B  8 = 9B + 10 or 2B = 18 making B = 9.
From B  A = 8, 9  A = 8 making A = 1 or the number = 19. 
Anonymous
too easy

Anonymous
Let unit digit = x
Then tens did it = 8+x
Original no.is 10(8+x)+x
80+10x+x=80+11x
On reversing : 10x+8+x =11x+8
11x+8=10+9x
11x9x=108
2x=2
X=1
No.is 80+11x=80+11=91
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