Math
posted by Candice Watt
A 30% solution of fertilizer is to be mixed with a 60% solution of fertilizer in order to get 150 gallons of 50% solution. How many gallons of the 30% and the 60% solutions should be mixed. I really need help.

helper
x = gal of 30% solution
.30x = value of 30% solution
150  x = gal of 60% solution
.60(150  x)
.50(150) = mixture
.30x + .60(150  x) = .50(150)
Solve for x, gal of 30% solution
150  x = gal of 60% solution
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