Math

posted by Candice Watt

A 30% solution of fertilizer is to be mixed with a 60% solution of fertilizer in order to get 150 gallons of 50% solution. How many gallons of the 30% and the 60% solutions should be mixed. I really need help.

  1. helper

    x = gal of 30% solution
    .30x = value of 30% solution
    150 - x = gal of 60% solution
    .60(150 - x)
    .50(150) = mixture

    .30x + .60(150 - x) = .50(150)

    Solve for x, gal of 30% solution
    150 - x = gal of 60% solution

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