Algebra- is my answer right
posted by Jen .
Graph the Circle
x^2+y^2+4x-2y-20=0
I get:
(x^2+4x)+(y^2-2y)=20
(x^2+4x+4)+(y^2-2y+1)=20+16+4
(x+2)^+(y-1)^2=(40/2)^2
But I don't think its right can you help me with what I did wrong? Thanks
posted by Jen .
Graph the Circle
x^2+y^2+4x-2y-20=0
I get:
(x^2+4x)+(y^2-2y)=20
(x^2+4x+4)+(y^2-2y+1)=20+16+4
(x+2)^+(y-1)^2=(40/2)^2
But I don't think its right can you help me with what I did wrong? Thanks