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A fox fleeing from a hunter encounters a 0.625 m tall fence and attempts to jump it. The fox jumps with an initial velocity of 7.75 m/s at an angle of 45.0°, beginning the jump 1.82 m from the fence. By how much does the fox clear the fence? Treat the fox as a particle.

  • physics -

    Y = ver = 7.75sin45 = 5.48m/s.

    (Vf)^2 = (Vi)^2 + 2gd = 0,
    (5.48)^2 + 2(-9.8)d = 0,
    30.03 - 19.6d = 0,
    -19.6d = -30.03,
    d(up) = -30.03 / -19.6 = 1.53m.

    Margin = 1.53 - 0.625 = 0.91m.

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