physics
posted by Anonymous .
A fox fleeing from a hunter encounters a 0.625 m tall fence and attempts to jump it. The fox jumps with an initial velocity of 7.75 m/s at an angle of 45.0°, beginning the jump 1.82 m from the fence. By how much does the fox clear the fence? Treat the fox as a particle.

Y = ver = 7.75sin45 = 5.48m/s.
(Vf)^2 = (Vi)^2 + 2gd = 0,
(5.48)^2 + 2(9.8)d = 0,
30.03  19.6d = 0,
19.6d = 30.03,
d(up) = 30.03 / 19.6 = 1.53m.
Margin = 1.53  0.625 = 0.91m.
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