Mr Chee deposited $80 into his checking account. Then, after writing a $23 check for gas and a $90 check for his child's day care, the balance in his account was $67. How much was in his account before he made the deposit? How would you solve and check the answer?
OriginalBalance+80-23-90=67
solve for originalbalance.
To solve this problem, we will use a basic algebraic approach. Let's assume the initial amount in Mr Chee's account before his deposit is 'x'.
Step 1: Calculate the balance after the deposit
Mr Chee deposited $80, so the balance after the deposit would be (x + $80).
Step 2: Deduct the amounts of the checks written
From the balance after the deposit, we deduct the amount of the gas check ($23) and the daycare check ($90). This gives us the final balance, which is $67.
Thus, the equation becomes:
(x + $80) - $23 - $90 = $67
Step 3: Solve the equation
Simplifying the equation, we have: x - $33 = $67
Now, we isolate x by adding $33 to both sides of the equation:
x - $33 + $33 = $67 + $33
x = $100
Therefore, the initial amount in Mr Chee's account before the deposit was $100.
To check our answer, we can follow the same steps and see if they lead to the given final balance of $67.
Step 1: Deposit $80 into the account:
Initial amount = $100
Deposit = $80
Balance after the deposit = $100 + $80 = $180
Step 2: Deduct the check amounts:
Balance after the deposit - $23 (gas check) - $90 (daycare check) = $180 - $23 - $90 = $67
The final balance after deducting the checks is indeed $67, confirming that the initial amount in Mr Chee's account was $100.