Two instruments are playing musical note "A" (440 Hz). A beatnote with a frequency of 2.5 Hz is heard. Assuming that one instrument is playing the correct pitch, what is the frequency of the pitch played by the second instrument?
F = 440 +- 2.5 = 442.5Hz or 437.5Hz.
To find the frequency of the pitch played by the second instrument, we first need to understand what causes a beatnote. When two sound waves with slightly different frequencies combine, they interfere with each other, resulting in a beat frequency.
In this scenario, the beatnote frequency is given as 2.5 Hz. This means that the difference between the frequencies of the two instruments is 2.5 Hz.
Let's denote the frequency of the pitch played by the second instrument as f2. We already know that the frequency of the first instrument is 440 Hz.
Now we can set up an equation based on the information given:
f2 - 440 Hz = 2.5 Hz
To find f2, we can isolate it by moving the constants to the other side of the equation:
f2 = 440 Hz + 2.5 Hz
Simplifying the equation, we get:
f2 = 442.5 Hz
Therefore, the frequency of the pitch played by the second instrument is 442.5 Hz.