what is the least common multiple (LCM)for 15 and 45?

There are 16 girls in a class of 36 student. which expression could be used to determine the number of boys (b) in the class?

please! help i think this too hard for 5th grade math. this suppose to be for 10th or college level instead of me..i don't even understnd this problem.

These are not college or high school problems. They are part of the normal 5th grade curricula.

Check this site for LCM instructions.

http://www.mathsisfun.com/least-common-multiple.html

Let x = the number of boys in the class.

36 - 16 = x

I agree with Ms. Sue. These are definitely in a good 5th grade math curriculum. My granddaughter is in 5th grade this year, and she has had this level of work for over a year now.

can you show how to do the median ?

what is the median for the following numbers?

142,83,65,178,14,78.
i think 83 is the answer.

36/16=B THE ANSWER FOR EXPRESSION FOR .36 STUDENTS 36/16=20 BOYS THE ANSWER

http://www.purplemath.com/modules/meanmode.htm

"The median is the middle number. In this example, the numbers are already listed in numerical order, so I don't have to rewrite the list. But there is no "middle" number, because there are an even number of numbers. In this case, the median is the mean (the usual average) of the middle two values: (2 + 4) ÷ 2 = 6 ÷ 2 = 3"

14, 65, 78, 83, 142, 178
So you need to find the average (mean) between 78 and 83. How will you do that?

LCM=3

let x=total students
let y=total girls
let z=total boyz

z=x-y
z=36-16
z=10

Visitors to an art musuem were asked to

name a favorite type of art.Pottery was
named by 9/40 of the visitors, paonting
was named by 2/5, and sculpture was
named by 3/8. What was the favorite type of art of most visitors ?

THIS IS SOOOOO HARD !!!! PlEaSe HeLp

lcm=45

36-16=boys

By the way i learned this before 5th grade

This seems very easy..

No worries! I'm here to help you understand. Let's break it down step by step.

To find the least common multiple (LCM) for 15 and 45, you can follow these steps:

Step 1: Find the prime factors of both numbers.
- The prime factors of 15 are 3 and 5.
- The prime factors of 45 are 3, 3, and 5.

Step 2: Take the highest power of each prime factor.
- Since 15 has a power of 1 for both 3 and 5, we take them as they are.
- Since 45 has a power of 2 for 3 and a power of 1 for 5, we take the higher power and ignore the lower power.

Step 3: Multiply the highest powers together.
- So, 3^1 * 5^1 = 3*5 = 15.

Therefore, the least common multiple (LCM) for 15 and 45 is 15.

Now, for the second question about finding the number of boys in the class, we can use an algebraic expression:

Let b represent the number of boys in the class. Since there are 36 students in total and 16 of them are girls, the number of boys can be determined by subtracting the number of girls from the total number of students.
So, the expression would be: b = 36 - 16.

I hope this explanation helps you understand how to find the LCM and solve the problem in your 5th-grade math class. Don't hesitate to ask if you have any further questions!