algebra
posted by Bri .
you will be making hanging flower baskets. the plants you have picked out are blooming annuals and nonblooming annuals. the blooming annuals cost $3.20 each and the nonblooming annuals cost $1.50 each. you bought a total of 24 plants for $49.60. write a linear system of equations that you can use to find out how many of each type of plant you bought.

b = number of blooming annuals
n = number of nonblooming annuals
3.20b = value of blooming
1.50n = value of nonblooming
b + n = 24
3.20b + 1.50n = 49.60
Solve the system 
i do not think that is what my teacher was asking for.

"write a linear system of equations"
This is a linear system of equations.
You can use x and y instead of n and b.
x = number of blooming annuals
y = number of nonblooming annuals
3.20x = value of blooming
1.50y = value of nonblooming
x + y = 24
3.20x + 1.50y = 49.60
Then solve the system.
Have you learned solving simultaneous equations?
This can also be solved using one equation, but the problem asked for a linear system of equations. 
ya i did today. but i don't understand how you got 24 as the yintercept

24 is the total number of plants.
x = number of blooming annuals
y = number of nonblooming annuals
x + y = 24 
okaaaay im starting to get it. so what would the second equation be again? and can you please explain it? =) thanks!

3.20x = value of blooming annuals
3.20 each plant * x number of plants = ttl cost
1.50y = value of nonblooming annuals
1.50 each plant * y number of plants = ttl cost
3.20x + 1.50y = 49.60 
ok thanks!
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