calculate the force exerted on a rocket given that the propelling gases are expelled at a rate of 1000 kg/s with a speed of 60,000 m/s.

The thrust developed derives from

F = Ve(w)/g where F = thrust, w = the propelant flow rate and g = the acceleration due to gravity.

it is just F= V(flow rate)

U don't divide by the gravity

To calculate the force exerted on a rocket, we need to use Newton's second law of motion, which states that force (F) is equal to the rate of change of momentum (Δp) over time (Δt).

Momentum (p) is calculated as the product of mass (m) and velocity (v):

p = m * v

In this case, the propelling gases are expelled at a rate of 1000 kg/s with a speed of 60,000 m/s. So, the mass of the gases expelled per second is 1000 kg/s, and their velocity is 60,000 m/s.

To find the force exerted by the propelling gases, we need to find the rate of change of momentum (Δp). Since momentum is a vector quantity, we need to consider the direction of the expelled gases opposite to the direction of the rocket's motion. Therefore, the change in momentum is given by:

Δp = (m * -v) - (m * 0)
= -m * v

Now, we have both the rate of change of momentum (Δp) and the time (Δt) taken for the propelling gases to be expelled. As the time taken is not specified, we will assume it to be 1 second for simplicity.

Δt = 1 second

Using Newton's second law, we can calculate the force (F):

F = Δp / Δt

F = -m * v / Δt

Substituting the given values:

F = -1000 kg/s * 60,000 m/s / 1 second
F = -60,000,000 N

Since the negative sign indicates that the force is in the opposite direction of the expelled gases, we can state that the force exerted on the rocket is 60,000,000 N in the opposite direction of the expelled gases.