A 5.0g silver spoon at 20.0C is placed in a cup of coffee at 90.0C. How much heat does the spoon absorb from the coffee to reach a temperature of 89.0C?
Q = heat gained by silver
= (Specific Heat of silver)*5g * 79 C
= ?
The specific heat of silver is 0.237 J/gC
Q = 93.6 J
= 22.4 calories
Make sure your 5.0 g mass is correct. The question has been asked before with a more believable mass of 50 g.
To calculate the heat absorbed by the spoon to reach a temperature of 89.0°C, we can use the formula:
Q = mcΔT
where:
Q = heat absorbed (in Joules)
m = mass of the spoon (in grams)
c = specific heat capacity of silver (in J/g°C)
ΔT = change in temperature (final temperature - initial temperature)
Given:
mass of the spoon (m) = 5.0 g
specific heat capacity of silver (c) = 0.235 J/g°C
initial temperature (T initial) = 20.0°C
final temperature (T final) = 89.0°C
First, let's calculate the change in temperature:
ΔT = T final - T initial
= 89.0°C - 20.0°C
= 69.0°C
Now, we can calculate the heat absorbed by the spoon:
Q = mcΔT
= (5.0 g) * (0.235 J/g°C) * (69.0°C)
= 812.325 Joules
Therefore, the spoon absorbs approximately 812.325 Joules of heat from the coffee to reach a temperature of 89.0°C.
To calculate the amount of heat absorbed by the silver spoon, we can use the equation:
Q = mcΔT,
where Q represents the heat absorbed, m is the mass of the spoon, c is the specific heat capacity of silver, and ΔT is the change in temperature.
Given:
Mass of the spoon (m) = 5.0g
Specific heat capacity of silver (c) = 0.235 J/g°C
Temperature change (ΔT) = 89.0°C - 20.0°C = 69.0°C
Now, substitute the values into the equation:
Q = (5.0g) * (0.235 J/g°C) * (69.0°C),
Q = 808.725 J.
Therefore, the silver spoon absorbs approximately 808.725 Joules of heat from the coffee to reach a temperature of 89.0°C.