Hi, could someone help me with these calculations for my lab;
Given: Volume of vinegar analyzed:5 mL
Con'c of NaOH: 0.09890M
Avg. V of NaOH from titration:43.75 mL
Moles of NaOH required to reach the equivalence point: ? Would this be (0.09890M)(0.04375L)=0.004327 moles
Moles of acetic acid 5.00mL of vinegar:? Would this be (0.0500L)(60.0g/mol)...not sure
Mass of acetic acid in the 5.00mL sample of vinegar: ? Would this be (0.004327 moles)(60.0g/mol)=0.2596g
Volume of the acetic acid in the 5.00mL sample of vinegar:? Not sure
% by volume of acetic acid in the vinegar:?
Yes and no.
moles NaOH = M x L and you are correct.
moles CH3COOH must be the same.
grams CH3COOH = molx x molar mass.
Thus, that is grams CH3COOH in 5 mL if you titrated a 5.00 mL sample. You want to know the g/100 mL for % w/v.
grams in 100 mL = grams in 5 mL x 20 = ?? (because grams x (100/5) = ??)
Sure, I can help you with these calculations.
To find the moles of NaOH required to reach the equivalence point, you can use the equation:
Moles of NaOH = (Concentration of NaOH) × (Volume of NaOH from titration)
So in this case, it would be (0.09890 M) × (0.04375 L) = 0.004327 moles.
To find the moles of acetic acid in the 5.00 mL of vinegar, you can use the equation:
Moles of acetic acid = (Volume of vinegar analyzed) × (Concentration of NaOH)
So it would be (0.005 L) × (0.09890 M) = 0.0004945 moles.
Next, to find the mass of acetic acid in the 5.00 mL sample of vinegar, you can use the equation:
Mass of acetic acid = (Moles of acetic acid) × (molar mass of acetic acid)
The molar mass of acetic acid is approximately 60.0 g/mol, so it would be (0.0004945 moles) × (60.0 g/mol) = 0.02967 g.
To find the volume of the acetic acid in the 5.00 mL sample of vinegar, you can use the concept of density:
Density = Mass / Volume
As you have already found the mass of acetic acid (0.02967 g), you can rearrange the equation to solve for volume:
Volume of acetic acid = Mass of acetic acid / Density
You would need to know the density of acetic acid to calculate this.
Finally, to find the % by volume of acetic acid in the vinegar, you can use the formula:
% by volume = (Volume of acetic acid / Volume of vinegar analyzed) × 100
Again, you would need to know the volume of acetic acid to calculate this.
I hope this helps! Let me know if you have any further questions.