posted by Anonymous .
A race car traveling northward on a straight, level track at a constant speed travels 0.750km in 20.0s. The return trip over the same track is made in 25.0s. What is the average velocity of the car in m/s for the first leg of the run? What is the average velocity for the total trip?
Average velocity = (displacement vector)/(elapsed time)
In the first case, there is a displacement of 0.75 km north.
In the second case, there is zero displacement. You end up where you started. 0/45 = ?
Trick question? Perhaps