Post a New Question

Calculus

posted by .

Find the area enclosed by the following functions from x=0 to x=2:

y=sqrt*(x+2)
y=1/(1+x)

I got
2/3(8)-ln3-2/3(sqrt*8)
can someone please verify this?

  • Calculus -

    2/3(8)-ln3-2/3(sqrt*8)

    My answer,
    16/3 - ln 3 - 4/3(sqrt(2))


    You have 16/3,
    2/3 (8) = 16/3

    Where you went wrong,
    You have, 2/3 (sqrt(8))
    It should be,
    2/3 (0 + 2)^3/2
    2/3 (2)^3/2
    2/3 (sqrt(2))^3
    2/3 (2(sqrt(2)))
    4/3 (sqrt(2))

  • Calculus -

    Perfect, thanks!
    I agree that your answer is more simplified..
    but my answer is definitely not wrong because
    2/3(sqrt(8)) and 4/3(sqrt(2)) are the same.

    Because.. 8=4x2 and sqrt of 4 is 2.. so you take 2 out of the sqrt to be 2. 2x2 is 4. so you end up with 4/3(sqrt(2)). Do you agree?

  • Calculus -

    I guess it depends on your teacher, because

    (2)^3/2 means (sqrt(2))^3

    I've never seen anyone interpret this as
    (sqrt(2^3)).

    The first way will always get you the correct, simplified answer. If I were you, I would get in the habit of doing this the first way.

    Radicals should always be in the lowest terms. Any teacher I had would take off half credit for your answer.

    Good luck.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. math calculus please help!

    l = lim as x approaches 0 of x/(the square root of (1+x) - the square root of (1-x) decide whether: l=-1 or l=0 or l=1 Let me make sure I understand the question. Do we have lim x->0 x/[sqrt(1+x) - sqrt(1-x)] ?
  2. Math(Roots)

    sqrt(24) *I don't really get this stuff.Can somebody please help me?
  3. math,algebra,help

    Directions are simplify by combining like terms. x radiacal 18 -3 radical 8x^2 can someone show me how to do these types of problems. thanks I cant determine the second term. For the first, I think you meant x sqrt(18) which reduces …
  4. Math Help please!!

    Could someone show me how to solve these problems step by step.... I am confused on how to fully break this down to simpliest terms sqrt 3 * sqrt 15= sqrt 6 * sqrt 8 = sqrt 20 * sqrt 5 = since both terms are sqrt , you can combine …
  5. Calculus

    Please look at my work below: Solve the initial-value problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/- Sqrt(4^2-4(1)(6)))/2(1) r=(16 +/- Sqrt(-8)) r=8 +/- Sqrt(2)*i, alpha=8, Beta=Sqrt(2) y(0)=2, e^(8*0)*(c1*cos(0)+c2*sin(0))=c2=2 …
  6. Math/Calculus

    Solve the initial-value problem. Am I using the wrong value for beta here, 2sqrt(2) or am I making a mistake somewhere else?
  7. Calculus

    Evaluate the indefinite integral: 8x-x^2. I got this but I the homework system says its wrong:sqrt((-x-8)x)/(2*sqrt(x-8)*sqrt(x))*(((sqrt(x-8)*(x-4)*sqrt(x))-32*log(sqrt(x-8)+sqrt(x))
  8. Check my CALCULUS answers please!

    Any short explanation for things I got wrong would be great, too, if possible! Thanks in advanced! :) 8. Which of the following functions grows the fastest?
  9. Calculus check

    Given f(x)=x^4(2x^2-15). On what interval(s) is the graph of f concave upwards?
  10. linear algebra urgent

    For the orthogonal matrix A = 1/sqrt(2) -1/sqrt(2) -1/(sqrt(2)) -1/sqrt(2) verify that (Ax,Ay)=(x,y) for any vectors x and y in R2. Can someone please explain this

More Similar Questions

Post a New Question