# trig

posted by .

Given that sin x = - ã2/2 and that cos x is negative, find the other functions of x and the value of x.

can you explain how this problem can be solved please.

• trig -

Do you mean -(sqrt(2))/2 ?

• trig -

yes

okay i know that this is in the 3rd quadrant with reference angle 45
so i understand the first part but what i don't get is how i can find the value can you please explain.

• trig -

sides of triangle are sqrt 2, sqrt 2 , 2 so
cos x also = -sqrt 2 / 2
tan = sin / cos
sec = 1/cos
csc = 1/sin
ctn = 1/tan

• trig -

sin = -sqrt 2 / 2
cos = -sqrt 2 / 2
tan = 1
cot = 1
sec = -sqrt 2
csc = -sqrt 2

is that right ?
okay now how can i find the value?

• trig -

yes. Sqrt 2 is approximately 1.41

• trig -

x = 180 + 45 in degrees
= (1 1/4) pi in radians

• trig -

thanks for your time but they are also asking for the value of x which i think they mean the value of x in degrees ??

• trig -

thank you.

• trig -

x = 225 degrees

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