trig

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Given that sin x = - ã2/2 and that cos x is negative, find the other functions of x and the value of x.


can you explain how this problem can be solved please.

  • trig -

    Do you mean -(sqrt(2))/2 ?

  • trig -

    yes

    okay i know that this is in the 3rd quadrant with reference angle 45
    so i understand the first part but what i don't get is how i can find the value can you please explain.

  • trig -

    sides of triangle are sqrt 2, sqrt 2 , 2 so
    cos x also = -sqrt 2 / 2
    tan = sin / cos
    sec = 1/cos
    csc = 1/sin
    ctn = 1/tan

  • trig -

    sin = -sqrt 2 / 2
    cos = -sqrt 2 / 2
    tan = 1
    cot = 1
    sec = -sqrt 2
    csc = -sqrt 2

    is that right ?
    okay now how can i find the value?

  • trig -

    yes. Sqrt 2 is approximately 1.41

  • trig -

    x = 180 + 45 in degrees
    = (1 1/4) pi in radians

  • trig -

    thanks for your time but they are also asking for the value of x which i think they mean the value of x in degrees ??

  • trig -

    thank you.

  • trig -

    x = 225 degrees

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