A charge of +q is placed at y = 0 m. Another charge of +2q (twice the other charge) is placed at y = +6.52 meters. Where on the y axis is the total electric field zero?
Somewhere on the y axis between the two charges there E fields due to each particle are equal and opposite. Use Coulomb's law to fnd that location.
q/y^2 = 2q/(6.52 - y)^2
Solve for y