calc II
posted by Anonymous .
Find the arc length of the graph of the function over the interval [1,2].

Without telling us what the function is, how do you expect us to come up with an answer?
Respond to this Question
Similar Questions

calc
Consider the function below. (Round the answers to two decimal places. f(x) = 2x tan(x) p/2 < x < p/2 (a) Find the interval where the function is increasing. Find the interval where the function is decreasing. (b) Find the local … 
Calc
Find the arc length of the graph of the function over the indicated interval. y = (x⁵/10)  (1/(6x³)) , [1,20] Thank you so much!! 
calculus
Find the arc length of the graph of the function over the indicated interval. (Round your answer to three decimal places.) y = ln (sin(x)) ,[π/4,3π/4] 
calculus
Find the arc length of the graph of the function over the indicated interval. (Round your answer to three decimal places.) y = (2/3)x^(3/2) +7 ;[0,6] 
calc arc length
Find the length of the arc along f(x) = integral from 0 to x^3 sqrt(cos t) dt on the set of x [0, pi/3]. 
Math: Calc 2
Find the volume of the solid obtained by rotating the region under the graph of the function f(x) = x^(13/12) about the xaxis over the interval [1,3]. Thanks! 
Calculus 2
find the arc length of the graph of the function over the indicated interval. x^5/10+1/(6x^3) on the interval (3,6) 
AP Calc B/C
Find the arc length of one arch of the sine curve. I started it by doing y=sinx, y'=cosx arc length= integral of sqrt(1+cos^2x)dx from pi/2 to 3pi/2 but I don't know how to integrate that! Thank you! 
Calc
Use the limit process to find the area of the region between the graph of the function and the xaxis over the given interval. y = −4x + 6, [0, 1] 
Calculus AP Exam review explanation pls
1)What is the area bounded by y = x^2 and y =3x?