posted by jdajaljk .
A 10 kg block is allowed to slide down a ramp with uk = 0.15.
a. What is the value of the frictional force opposing the block's slide down the ramp?
b. What is the acceleration of the block?
After you have learned how to compute the frictional force, and applied
F(net) = ma in the downward direction along the ramp, feel free to post your work for critical evaluation.
We are not going to do it for you.
1.41 N=(10 kg) a
Good work. I almost didn't see the decimal point in front of .141
It would be better to write it as 0.141 m/s^2. It is easier to read that way.
I don't understand why the normal force is 9.4. If the object weighs 10 kg, the Fg in the y direction should be 92.1N, correct which would make the Fn 92.1N as well.
I agree with Claire. My final answer for the acceleration was 1.97m/s^2